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The roots of the quadratic equation 3x^2...

The roots of the quadratic equation `3x^2 - 5x + 2 = 0` are

A

`(2/3,1)`

B

`(1,1)`

C

`(1/3, 1)`

D

none of these

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The correct Answer is:
To find the roots of the quadratic equation \(3x^2 - 5x + 2 = 0\), we can use the quadratic formula or factorization. Here, we will use the factorization method. ### Step-by-Step Solution: 1. **Identify the coefficients**: The given quadratic equation is in the form \(ax^2 + bx + c = 0\), where: - \(a = 3\) - \(b = -5\) - \(c = 2\) 2. **Calculate the product \(ac\)**: We need to find two numbers that multiply to \(ac\) (which is \(3 \times 2 = 6\)) and add up to \(b\) (which is \(-5\)). \[ ac = 3 \times 2 = 6 \] 3. **Find two numbers**: We are looking for two numbers that add to \(-5\) and multiply to \(6\). The numbers are \(-2\) and \(-3\) because: \[ -2 + (-3) = -5 \quad \text{and} \quad -2 \times -3 = 6 \] 4. **Rewrite the middle term**: We can rewrite the equation by splitting the middle term using the two numbers found: \[ 3x^2 - 2x - 3x + 2 = 0 \] 5. **Group the terms**: Now, we group the terms: \[ (3x^2 - 2x) + (-3x + 2) = 0 \] 6. **Factor by grouping**: Factor out the common terms from each group: \[ x(3x - 2) - 1(3x - 2) = 0 \] This can be factored as: \[ (3x - 2)(x - 1) = 0 \] 7. **Set each factor to zero**: Now, we set each factor equal to zero: \[ 3x - 2 = 0 \quad \text{or} \quad x - 1 = 0 \] 8. **Solve for \(x\)**: For \(3x - 2 = 0\): \[ 3x = 2 \quad \Rightarrow \quad x = \frac{2}{3} \] For \(x - 1 = 0\): \[ x = 1 \] 9. **Conclusion**: The roots of the quadratic equation \(3x^2 - 5x + 2 = 0\) are: \[ x = \frac{2}{3} \quad \text{and} \quad x = 1 \] ### Final Answer: The roots are \(x = \frac{2}{3}\) and \(x = 1\). ---
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