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Four coins are tossed. The chance of get...

Four coins are tossed. The chance of getting none of the face as head is

A

`(1)/(16)`

B

`(1)/(8)`

C

`(1)/(6)`

D

`(3)/(4) `

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The correct Answer is:
To find the probability of getting none of the faces as heads when four coins are tossed, we can follow these steps: ### Step 1: Understand the total outcomes When a coin is tossed, there are two possible outcomes: Heads (H) or Tails (T). For four coins, the total number of outcomes can be calculated using the formula for the number of outcomes in a sequence of independent events, which is \(2^n\), where \(n\) is the number of coins. **Total outcomes** = \(2^4 = 16\) ### Step 2: Identify the favorable outcomes We want to find the probability of getting none of the coins showing heads. This means all coins must show tails. There is only one favorable outcome for this scenario, which is Tails for all four coins (TTTT). **Favorable outcomes** = 1 (only TTTT) ### Step 3: Calculate the probability The probability \(P\) of an event is given by the formula: \[ P(\text{Event}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \] Substituting the values we found: \[ P(\text{None heads}) = \frac{1}{16} \] ### Final Answer The chance of getting none of the faces as heads when four coins are tossed is \(\frac{1}{16}\). ---
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