If 10 g of ice at 0^(@)C is mixed with 1...

If 10 g of ice at `0^(@)`C is mixed with 10 g of water at `10^(@)`C, the final temperature `t` is given by

A

`10 xx 80 = 10 ( 10 -t ) + 10 ( t - 0)`

B

`t = 5^(@)` C

C

`t = 0^(@)`C

D

`10 xx 80 + 10 ( t -0) = 10 ( 10 -t)`

Verified by Experts

The correct Answer is:

D

`Q_1 = 10 xx 1 xx 10 = 100` cal
`Q_2 = 10 xx 80 = 800` cal
As `Q_1 lt Q_2`, so final temperature `t = 0^(@)` C

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