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When light rays are incident on a prism ...

When light rays are incident on a prism at an angle of `45^(@)`, the minimum deviation is obtained. If refractive index of the material of prism is `sqrt(2)`, then the angle of prism will be

A

`30^(@)`

B

`40^(@)`

C

`50^(@)`

D

`60^(@)`

Text Solution

Verified by Experts

The correct Answer is:
D

`"As ",mu=sin((A+delta)/2)/(sin(A/2))`
Where , `delta` denotes minimum deviation. In minimum deviation position,
`"As ",i=((A+delta)/(2))implies45^(@)=((A+delta)/(2))`
`therefore" "mu=(sin45^(@))/(sin(A/2))impliessqrt2=(1)/(sqrt2.sin(A/2))`
`impliessin(A/2)=1/2=sin30^(@)`
`impliesA=60^(@)`
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