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Angle of minimum deviation for a prism o...

Angle of minimum deviation for a prism of refractive index 1.5 is equal to the angle of prism The angle of prism is `(cos 41^(@) = 0.75)`

A

`62^(@)`

B

`41^(@)`

C

`31^(@)`

D

`82^(@)`

Text Solution

Verified by Experts

The correct Answer is:
D
`"As ",mu=sin((A+delta)/2)/(sin(A/2))`
`implies1.5=sin((A+A)/(2))/(sin(A/2))=(sinA)/(sin(A/2))`
`(2sin(A/2)cos(A/2))/(sin(A/2))`
`"or ",1.5=2.cos(A/2)`
`impliescos(A/2)=(1.5)/(2)=0.75=cos41^(@)`
`implies(A/2)=41^(@)impliesA=82^(@)`
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