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If a 0.1 % increase in length due to str...

If a `0.1 %` increase in length due to stretching, the percentage increase in its resistance will be

A

`0.2%`

B

`2%`

C

`1%`

D

`0.1%`

Text Solution

Verified by Experts

The correct Answer is:
A

As, `R=(rhol)/S` For a given wire, `rho` and volume V are constant. Take log and differentiate for small variations.
`R=(rhol)/"(volume/l)"=(rl^2)/"volume"`
`logR=2logl+log(rho/"volume")`
`(dR)/R=(2dl)/l`
For determining percentage, put R = 100
`therefore (dR)/(100)=2xx(0.1)/(100)rArrdR=0.2%`
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