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The cell has an emf of 2 V and the inter...

The cell has an emf of 2 V and the internal resistance of this cell is 0.1`Omega`, it is connected to resistance of 3.9`Omega`, the voltage across the cell will be

A

1.95 V

B

1.90 V

C

0.50 V

D

2.00 V

Text Solution

Verified by Experts

The correct Answer is:
A
As, `E=l(R+r)rArr2=l(3.9+0.1)=4l`
`rArr" "l=2/4=1/2`
From, `V=lr`
`rArr" "V=1/2xx3.9=1.95`V
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