Two equal and opposite charges attract each other by a force F. If half of the charge from one is transferred to the other without changing distance between the charges, the force between the charges now become

Options

A. F
B. `(3F)/(4)`
C. `(F)/(2)`
D. `(F)/(4)`

Answer

B

Explanation

Let `q_(1)= q_(2)=q`
`:. F = (1)/(4piepsilon_(0))(q^(2))/(r^(2))`
According to question, `q_(1)= (q)/(2)` and `q_(2)= (3q)/(2)`
Now force,
`F_(1)= (1)/(4piepsilon_(0))((q)/(2).(3q)/(2))/(r^(2))`
`F_(1)= (3)/(4)(1)/(4piepsilon_(0))(q^(2))/(r^(2))` ....(ii)
From Eqs. (i) and (ii)
`F_(1)= (3)/(4)F`