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Work done in stretching a spring of cons...

Work done in stretching a spring of constant k by x is, `(1)/(2) kx^(2)`. The work done when above spring is stretched further from x to 2x is

A

`(1)/(2)kx^(2)`

B

`kx^(2)`

C

`(3)/(2)kx^(2)`

D

`2 kx^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
We have,
`W_(1)= (1)/(2) kx^(2)` ….(i)
Where, x= stretch distance of wire Now according to problem,
`W_(2)= (1)/(2)k(2x)^(2)= 2kx^(2)`
For, work done, to stretching from xto 2x
`W= W_(2)-W_(1)= 2kx^(2)- (1)/(2)kx^(2)= (3)/(2)kx^(2)`
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