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The heat required to change 1 g ice at 0...

The heat required to change 1 g ice at `0^(@)C` to `0^(@)C` water is `Q_(1)` and that heat required to convert 1 g boiling water at `100^(@)C` to `100^(@)C` steam, is `Q_(2)`, then what is true?

A

`Q_(1) gt Q_(2)`

B

`Q_(2) gt Q_(1)`

C

`Q_(1) = Q_(2)`

D

`Q_(1)= Q_(2)=0`

Text Solution

Verified by Experts

The correct Answer is:
B
Latent heat of fusion for Ice
`L_(1)= 80 xx 4.18 xx 10^(3) J//kg = 80 xx 4.18 J//g= 334.4 J//g`
Latent heat of vaporisation for water
`L_(2)= 536 xx 10^(3) xx 4.18 J//kg= 536 xx 4.18 J//g= 2240.48 J//g`
`Q_(1)= m xx L_(1)= 1 xx 334.4 = 334.4 J`
`Q_(2)= m xx L_(2)= 1 xx 2240.48 = 2240.48 J`
`:. Q_(2) gt Q_(1)`
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