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If a rigid body is travelling distance i...

If a rigid body is travelling distance in proportional to the square of time, then the acceleration of this rigid body is

A

constant

B

Increasing

C

zero

D

decreasing

Text Solution

Verified by Experts

The correct Answer is:
A
According to the question, Distance (D) = square of time `t^2`
`D = kt^2`
`v = (dD)/(dt) = (d)/(dt) (kt^2) = 2kt`
and acceleration `a = (dv)/(dt) = 2k`
Hence, the acceleration of rigid body remains constant (2k).
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