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The solubility of CaF2 in pure water is ...

The solubility of `CaF_2` in pure water is `2.3xx10^(-4)mol dm^(-3)`. Its solubility product will be :

A

`4.6xx10^(-4)`

B

`4.6xx10^(-8)`

C

`6.9xx10^(-12)`

D

`4.9xx10^(-11)`

Text Solution

Verified by Experts

The correct Answer is:
D
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