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The minimum value of f(x)=sin^4x+cos^4x...

The minimum value of
`f(x)=sin^4x+cos^4x, 0lexlepi/2` is :

A

`1/(2sqrt2)`

B

`1/4`

C

`-1/2`

D

`1/2`

Text Solution

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The correct Answer is:
D
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