Home
Class 12
MATHS
A stone of mass m is thrown vertically u...

A stone of mass m is thrown vertically upwards with a velocity of `9.8 ms^(-1)`. The height of the point where KE=PE is (`g=9.8ms^(-2)`)

A

9.8 m

B

4.9 m

C

2.45 m

D

2 m

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Similar Questions

Explore conceptually related problems

A stone is thrown vertically upwards with a velocity of 4.9 ms^(-1) . Calculate : the maximum height reached.

A ball is thrown vertically upwards with a velocity of 49 ms^-1 . Calculate :The maximum height to which it rises

A body is thrown vertically upward with a velocity of 9.8 m/s. Calculate the maximum height attained by the body. (g=9.8m//s^(2))

A stone is thrown vertically upwards with a velocity of 4.9 ms^(-1) . Calculate : the time taken to reach the ground.

A stone is thrown vertically upwards with a velocity of 4.9 ms^(-1) . Calculate : the time taken to reach the maximum height.

A stone of mass 0.4 kg is thrown vertically up with a speed of 9.8 ms^(-1) . Find the potential energy after half second.

A ball is thrown vertically upwards with a velocity of 10 ms^(-1) . It returns to the ground with a velocity of 9 ms^(-1) . If g=9.8 ms^(-2) , then the maximum height attained by the ball is nearly (assume air resistance to be uniform)

A body is throw vertically upward with a velocity of 9.8 m/s. Calculate the maximum height attained by the body.

A stone is thrown vertically upwards with a velocity of 4.9 ms^(-1) . Calculate : the velocity with which it returns to the ground.