2/(sqrt5),3/5,4/(5sqrt5),5/(25),?...

`2/(sqrt5),3/5,4/(5sqrt5),5/(25),?`

`6/(5sqrt5)`

`6/(125)`

`7/(25)`

`6/(25sqrt5)`

Text Solution

Verified by Experts

The correct Answer is:

The numerators of the given fractions are consecutive natural numbers

Therefore, the numerator of the missing fraction should be 6.
The denominator of each fraction is multiplied by `sqrt5` to obtain the denominator of the next fraction Le.

Therefore, the denominator of the missing fraction should be `25sqrt5`
Therefore, the missing term is `6/(25sqrt5)`

Topper's Solved these Questions

SERIES COMPLETION : NUMBER
LUCENT PUBLICATION|Exercise EXERCISE-1 (type-I : Difference Series)|29 Videos
SERIES COMPLETION : NUMBER
LUCENT PUBLICATION|Exercise EXERCISE-1(Type-II : Squares/Cubes Series )|12 Videos
SERIES COMPLETION : MIXED SERIES
LUCENT PUBLICATION|Exercise Exercise ( Type-V: Miscellaneous )|1 Videos
SITUATION REACTION TEST
LUCENT PUBLICATION|Exercise EXERCISE (DECISION MAKING )|5 Videos

Similar Questions

Explore conceptually related problems

If sintheta=2//3 , find the value of sectheta and costheta A. sqrt5//2,2//sqrt5 B. 2//sqrt5,3//5 C. 3sqrt5//5,sqrt5//3 D. 3//5,3sqrt5//5

Which of the following statement(s) is/are TRUE? I. 2/(3 sqrt5) II. 3/(2 sqrt5)<2/(3 sqrt3)<7/(4 sqrt5)

Simplify each of the following : (3)/(5-sqrt(3))+(2)/(5+sqrt(3)) (ii) (4+sqrt(5))/(4-sqrt(5))+(4-sqrt(5))/(4+sqrt(5))(sqrt(5)-2)/(sqrt(5)+2)-(sqrt(5)+2)/(sqrt(5)-2)

find the values of a and b in each of the following (i) (5+2sqrt3)/(7+4sqrt3) = a-6sqrt3 (ii) (3-sqrt5)/(3+2sqrt5)= asqrt5-(19/11) (iii) (sqrt2+sqrt3)/(3sqrt2-2sqrt3)=2-bsqrt6 (iv) (7+sqrt5)/(7-sqrt5)-(7-sqrt5)/(7+sqrt5)=a+(7/11)bsqrt5

If (4+3sqrt(5))/(sqrt(5))=a+b sqrt(5), bis

(2sqrt3+sqrt5)(2sqrt3+sqrt5)

(sqrt5-3)/(sqrt5+3)times(sqrt5-3)/(sqrt5-3)=?

The value of (7+3 sqrt5)/(3+sqrt5)-(7-3 sqrt5)/(3-sqrt5) lies between: (7+3 sqrt5)/(3+sqrt5)-(7-3 sqrt5)/(3-sqrt5) का मान किसके बीच में होगा

(sqrt(5)-2)(sqrt(3)-sqrt(5))

The sum sqrt((5)/(4)+sqrt((3)/(2)))+sqrt((5)/(4)-sqrt((3)/(2))) is equal to

LUCENT PUBLICATION-SERIES COMPLETION : NUMBER -EXERCISE-3

2/(sqrt5),3/5,4/(5sqrt5),5/(25),?
Text Solution
|
{:(7,6,49,36,2401,1296),(9,"(a)","(b)","(c)", " (d)"," (e)"):} What ...
Text Solution
|
{:(7,8,14(1)/(2),32(1)/(2),87(1)/(2),271(1)/(2)),(5,"(a)","(b)","(c)",...
Text Solution
|
{:(4,2.25,3.25,7.125,18.25,51.875),(7,"(a)","(b)","(c)", " (d)"," (e)"...
Text Solution
|
{:(3,40,176,537,1078,1079),(1,"(a)","(b)","(c)", " (d)"," (e)"):} Wh...
Text Solution
|
{:(3,5,22,13.5,35,19),(5,"(a)","(b)","(c)", "(d)","(e)"):} What will...
Text Solution
|
{:(9,10,16,57,212,1085),(2,"(a)","(b)","(c)", "(d)","(e)"):} What wi...
Text Solution
|
{:(7,20,46,98,202,410),(4,"(a)","(b)","(c)", "(d)","(e)"):} What wil...
Text Solution
|
{:(3,12,30,66,138,282),(7,"(a)","(b)","(c)", "(d)","(e)"):} What wil...
Text Solution
|
{:(2,3,10,39,172,885),(5,"(a)","(b)","(c)", "(d)","(e)"):} What will...
Text Solution
|
{:(3,5,22,13.5,35,19),(1,"(a)","(b)","(c)", "(d)","(e)"):} What will...
Text Solution
|
{:(2,3,7,25,121,721),(3,"(a)","(b)","(c)", "(d)","(e)"):} What will ...
Text Solution
|
{:(4,2,3,7.5,26.25,118.125),(6,"(a)","(b)","(c)", "(d)","(e)"):} Wha...
Text Solution
|
{:(12,30,120,460,1368,2710),(16,"(a)","(b)","(c)", "(d)","(e)"):} Wh...
Text Solution
|
{:(154,462,231,693,346.5,1039.5),(276,"(a)","(b)","(c)", "(d)","(e)"):...
Text Solution
|
{:(7,91,1001,7007,35035,105105),(14.5,"(a)","(b)","(c)", "(d)","(e)"):...
Text Solution
|
{:(582,574,601,537,662,446),(204,"(a)","(b)","(c)", "(d)","(e)"):} W...
Text Solution
|
{:(85,43,44,67.5,137,345),(125,"(a)","(b)","(c)", "(d)","(e)"):} Wha...
Text Solution
|