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1/3,4/9,7/(27),(10)/(81),?,(16)/(729)...

`1/3,4/9,7/(27),(10)/(81),?,(16)/(729)`

A

`(14)/(234)`

B

`(15)/(241)`

C

`(12)/(432)`

D

`(13)/(243)`

Text Solution

Verified by Experts

The correct Answer is:
D
The given sequence follows the pattern :
Thenumbersin thenumerator(top)areincreasedby 3 and multiplied by 3 in the denominator (bottom) in the fraction series.

Therefore, missing term =`(13)/(243)`
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