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The last 4 missing fractions in the seri...

The last 4 missing fractions in the series:
`1/2,1/6,1/(12),1/(20),1/(30),?,?,?,?,` are

A

`1/(40),1/(50),1/(60),1/(70)`

B

`1/(42),1/(56),1/(72),1/(90)`

C

`1/(44),1/(58),1/(74),1/(92)`

D

`1/(41),1/(55),1/(72),1/(90)`

Text Solution

Verified by Experts

The correct Answer is:
B
The given sequence of number follows the pattern :

Therefore , Missing fractions `= 1/(42),1/(56),1/(72),` and `1/(90)`
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