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Which term of the series 3, 8, 13, 18, 2...

Which term of the series 3, 8, 13, 18, 23 ... is 603 ?

A

101th

B

117th

C

106th

D

121th

Text Solution

Verified by Experts

The correct Answer is:
D
The given sequence is anA.P with first term
a = 3 and common difference = d = 8 - 3 = 13 - 8 = 5.
Let 603 be the nth term
`therefore` n th term = a + (n -1) d
or, 603 = a+ (n-1)d
Put a = 3, d = 5
`603 = 3 + (n -1) xx 5`
or, 603 = 3 + 5n - 5
or, 603 = 5n-2
or, 605 = 5n
or, `n = (605)/(5)=121`
Therefore, required term = 121th
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