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REASONING
Consider the following series. ABCD …X...

Consider the following series.
ABCD …XYZ | YX...BA |BCD... YZ | YZ...CBA | BC... YZ ...
Which letter occupies the 1000th position in the above series?

A

B

B

C

C

X

D

Y

Text Solution

Verified by Experts

The correct Answer is:
A
The given sequence of group of letters is a combination of letter series and follows the pattern.

Series I occur only once.
But, series II and III repeats alternately.
Therefore, required letter at 1000th position
= (1000- 26) + 25 = 38th pattern and 24 letters = 24th letter in series II i.e. in 39th pattern = B.
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