The power and square root places in the equation below require numbers to be inserted :
`2^(?) + sqrt? + (5)^2 = 48`

Options

A. 2, 36
B. 3,49
C. 4,25
D. 4,49

Answer

D

Explanation

The given equation can be written as
`2^(?) + sqrt? = 48 - (5)^2 = 23`
` therefore L.H.S = 2^(?) + sqrt?`
` R.H.S = 23`
Let the missing numbers in the power and square root places in the equation are `x_1` and `x_2` respectively.
Then, `L. H. S. = 2^(x_1)+ sqrt(x_2)`
Put `x_1 = 4, x_2 = 49`
So. L.H.S = `2^4 + sqrt49 = 16+7 = 23`
So, L.H.S = R.H.S
Therefore, Missing numbers are 4, 49.