Study the following information carefully and answer the given questions :
Four players A, B, C and Dare holding 4 cards each. Each of them has an Ace, a King, a Queen and a Jack. All of them have all the suits (spades, hearts, clubs and diamonds).
(i) A has Ace of spades and Queen of diamonds.
(ii) B has Ace of clubs and King of diamonds.
(iii) C has Queen of clubs and King of spades.
(iv) D has Jack of clubs.
Ace of diamonds is with

Options

A. A
B. B
C. C
D. D

Answer

D

Explanation

According to the given information :
Four suits `to` spades, hearts, clubs and diamonds
From (i), we get
`A overset("has")rarr` Ace of spades and Queen of diamonds
From (ii), we get
`Boverset("has")rarr` Ace of clubs and king of diamonds.
From (iii), we get
`hoverset("has")rarr` Queen of clubs and king of spades.
From (iv), we get
`D overset("has")rarr` Jack of clubs
So, `A overset("has")rarr` king of clubs , Ace of spades and king of diamonds.
`C overset("has")rarr` Ace of hearts, king of spades and queen of clubs.
[`because A overset("has")rarr` Jack of hearts]
`B overset("has")rarr` Ace of clubs, king of diamonds and Queen of hearts.
[`C overset("has")rarr` Jack Diamonds, `B overset("has")rarr` Queen of hearts]
By elimination, we get
`D overset("has")rarr` Ace of Diamonds, Jack of clubs, king of hearts and Queen of spades.

By analysing the above table, we get Ace of diamonds `overset("with")rarr` D.