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If A=[(a(11),a(12)),(a(21),a(22))], then...

If `A=[(a_(11),a_(12)),(a_(21),a_(22))]`, then minor of `a_(11) (i. e., M_(11))` is

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The correct Answer is:
`AB = [a_(11) xx b_(11) + a_(12) xx b_(21) + a_(13) xx b_(13) ]`
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