Solve `x ^(2) - ( 2 sqrt3 + 3i ) x + 6 sqrt3 i = 0`

Solve the following quadratic equations. x ^(2) - ( 3 sqrt2 + 2i ) x + 6 sqrt2 i =0

Find the value of x ^(3) - x ^(2) + 2x + 10 when x = 1 + sqrt3 i

Convert the complex numbers in polar form and also in exponential form. z = ( 2 + 6 sqrt3 i )/( 5 + sqrt3 i)

Solve the following: If a = (-1 + sqrt(3)i) / 2 , b = (-1 - sqrt(3)i) / 2 , show that a^2 = b and b ^2 = a

Express the follwing in the form of a + ib, a , b in R i=sqrt ( -1). State the value of a and b. ( - sqrt5 + 2 sqrt ( -4) ) + (1 - sqrt ( -9 ))+ (2 + 3i ) (2 - 3i )

int frac {x+1}{x+2} dx =............ A) x+2 - log(x+2) + c B) sqrt (x^2 + 3x +2) -(1/2) log x + (3/2) + sqrt (x^2 + 3x +2) + c C) sqrt (x^2 + 3x +2) +(1/2) log x + (3/2) + sqrt (x^2 + 3x +2) + c D) sqrt (x^2 + 3x +2) -(1/2) log x + (3/2) - sqrt (x^2 + 3x +2) + c

Solve: 4sqrt(3)x^(2)+5x-2sqrt(3)=0.

Solve the following quadratic equations: x^2 -(3 sqrt 2 +2i)x+6 sqrt 2 i=0

Solve the following equations: sqrt 3 x^2 - sqrt 2 x +3 sqrt 3 = 0