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Find sum(r=1)^n (1^2 + 2^2 + 3^2 +…….+ r...

Find `sum_(r=1)^n (1^2 + 2^2 + 3^2 +…….+ r^2) / (r + 1)`

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The correct Answer is:
`(n ( n+1) (2n + 9))/( 6)`
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