`3x + 4y - 10 = 0`
` 2x - 2y-2=0`

If (2, -2),(-1,2), (3,5) are the vertices of a triangle then the equation of the side not passing through (2,-2) is (A) x + 2y +1 = 0 (B) 2x - y- 4= 0 (C) X-3y -3= 0 (D) 3x – 4y + 11 = 0

3x + 4y = 10, 2x-2y = 2

Equation of radical axis of the circles x^(2) + y^(2) - 3x - 4y + 5 = 0 and 2x^(2) + 2y^(2) - 10x - 12y + 12 = 0 is

The equaiton of the lines representing the sides of a triangle are 3x - 4y =0 , x+y=0 and 2x - 3y = 7 . The line 3x + 2y = 0 always passes through the

Let circle cuts ortholognally each of the three circles x^(2) + y^(2) + 3x + 4y + 11 = 0, x^(2) + y^(2) - 3x + 7y - 1 = 0 and x^(2) + y^(2) + 2x = 0

Show that the lines 2x + 3y - 8 = 0 , x - 5y + 9 = 0 and 3x + 4y - 11 = 0 are concurrent.

The equation of the circle passing through (1/2, -1) and having pair of straight lines x^2 - y^2 + 3x + y + 2 = 0 as its two diameters is : (A) 4x^2 + 4y^2 + 12x - 4y - 15 = 0 (B) 4x^2 + 4y^2 + 15x + 4y - 12 = 0 (C) 4x^2 + 4y^2 - 4x + 8y + 5 = 0 (D) none of these

x- y + 3 = 0, 2x + 3y - 4 = 0 .