The value of `2 xx[3+ 2xx{3-(6div2)} + 7]` is

Options

A. 14
B. 20
C. 24
D. 34

Answer

To solve the expression \( 2 \times [3 + 2 \times \{3 - (6 \div 2)\} + 7] \), we will follow the order of operations (BODMAS/BIDMAS rules). Let's break it down step by step.

### Step-by-Step Solution:

1. **Identify the expression**:
\[ 2 \times [3 + 2 \times \{3 - (6 \div 2)\} + 7] \]

2. **Solve the innermost bracket**:
- Calculate \( 6 \div 2 \):
\[ 6 \div 2 = 3 \]
- Substitute back into the expression:
\[ 2 \times [3 + 2 \times \{3 - 3\} + 7] \]

3. **Continue with the brackets**:
- Now calculate \( 3 - 3 \):
\[ 3 - 3 = 0 \]
- Substitute back into the expression:
\[ 2 \times [3 + 2 \times 0 + 7] \]

4. **Calculate the multiplication inside the brackets**:
- Calculate \( 2 \times 0 \):
\[ 2 \times 0 = 0 \]
- Substitute back into the expression:
\[ 2 \times [3 + 0 + 7] \]

5. **Simplify the expression inside the brackets**:
- Now calculate \( 3 + 0 + 7 \):
\[ 3 + 0 + 7 = 10 \]
- Substitute back into the expression:
\[ 2 \times 10 \]

6. **Final multiplication**:
- Calculate \( 2 \times 10 \):
\[ 2 \times 10 = 20 \]

### Final Answer:
The value of the expression \( 2 \times [3 + 2 \times \{3 - (6 \div 2)\} + 7] \) is \( 20 \).

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