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The product of LCM and HCF of (3)/(5) an...

The product of LCM and HCF of `(3)/(5) and (8)/(3)` is

A

`(8)/(5)`

B

`(5)/(8)`

C

`(1)/(8)`

D

`(5)/(3)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the product of the LCM and HCF of the fractions \( \frac{3}{5} \) and \( \frac{8}{3} \), we will follow these steps: ### Step 1: Find the LCM of the numerators The numerators of the fractions are 3 and 8. To find the LCM of 3 and 8: - The prime factorization of 3 is \( 3^1 \). - The prime factorization of 8 is \( 2^3 \). The LCM is found by taking the highest power of each prime factor: - For 2, the highest power is \( 2^3 \). - For 3, the highest power is \( 3^1 \). Thus, \[ \text{LCM}(3, 8) = 2^3 \times 3^1 = 8 \times 3 = 24. \] ### Step 2: Find the HCF of the denominators The denominators of the fractions are 5 and 3. To find the HCF of 5 and 3: - The prime factorization of 5 is \( 5^1 \). - The prime factorization of 3 is \( 3^1 \). Since there are no common prime factors, the HCF is: \[ \text{HCF}(5, 3) = 1. \] ### Step 3: Calculate LCM of the fractions Now, we can find the LCM of the fractions: \[ \text{LCM}\left(\frac{3}{5}, \frac{8}{3}\right) = \frac{\text{LCM}(3, 8)}{\text{HCF}(5, 3)} = \frac{24}{1} = 24. \] ### Step 4: Find the HCF of the fractions Next, we find the HCF of the fractions: \[ \text{HCF}\left(\frac{3}{5}, \frac{8}{3}\right) = \frac{\text{HCF}(3, 8)}{\text{LCM}(5, 3)}. \] - The HCF of 3 and 8 is \( 1 \) (since they have no common factors). - The LCM of 5 and 3 is \( 15 \) (since \( 5 \times 3 = 15 \)). Thus, \[ \text{HCF}\left(\frac{3}{5}, \frac{8}{3}\right) = \frac{1}{15}. \] ### Step 5: Calculate the product of LCM and HCF Now we can find the product of the LCM and HCF: \[ \text{Product} = \text{LCM} \times \text{HCF} = 24 \times \frac{1}{15} = \frac{24}{15}. \] ### Step 6: Simplify the fraction To simplify \( \frac{24}{15} \): - Divide both the numerator and denominator by their HCF, which is 3: \[ \frac{24 \div 3}{15 \div 3} = \frac{8}{5}. \] ### Final Answer Thus, the product of the LCM and HCF of \( \frac{3}{5} \) and \( \frac{8}{3} \) is \( \frac{8}{5} \). ---
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