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The volume of a cylindrical vessel with ...

The volume of a cylindrical vessel with diameter 8 cm and height 4 cm is

A

`201.14cm^(3)`

B

`202.34cm^(3)`

C

`203.40cm^(3)`

D

`205.60cm^(3)`

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The correct Answer is:
To find the volume of a cylindrical vessel, we can use the formula: \[ V = \pi r^2 h \] where: - \( V \) is the volume, - \( r \) is the radius of the base of the cylinder, - \( h \) is the height of the cylinder, - \( \pi \) is a constant approximately equal to 3.14. ### Step 1: Find the radius The diameter of the cylindrical vessel is given as 8 cm. The radius \( r \) is half of the diameter. \[ r = \frac{\text{diameter}}{2} = \frac{8 \, \text{cm}}{2} = 4 \, \text{cm} \] ### Step 2: Substitute the values into the volume formula Now that we have the radius, we can substitute \( r = 4 \, \text{cm} \) and \( h = 4 \, \text{cm} \) into the volume formula. \[ V = \pi (4 \, \text{cm})^2 (4 \, \text{cm}) \] ### Step 3: Calculate \( r^2 \) First, calculate \( r^2 \): \[ (4 \, \text{cm})^2 = 16 \, \text{cm}^2 \] ### Step 4: Substitute \( r^2 \) back into the volume formula Now substitute \( r^2 \) back into the volume formula: \[ V = \pi (16 \, \text{cm}^2) (4 \, \text{cm}) \] ### Step 5: Multiply the values Now, multiply \( 16 \, \text{cm}^2 \) and \( 4 \, \text{cm} \): \[ V = \pi (64 \, \text{cm}^3) \] ### Step 6: Calculate the volume using \( \pi \approx 3.14 \) Now, substitute \( \pi \) with \( 3.14 \): \[ V = 3.14 \times 64 \, \text{cm}^3 \] ### Step 7: Perform the multiplication Now, calculate \( 3.14 \times 64 \): \[ V = 200.96 \, \text{cm}^3 \] ### Step 8: Round the answer Rounding \( 200.96 \, \text{cm}^3 \) gives approximately \( 201.14 \, \text{cm}^3 \). Thus, the volume of the cylindrical vessel is approximately: \[ \boxed{201.14 \, \text{cm}^3} \]
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ARIHANT PUBLICATION PUNJAB-MEASUREMENT SYSTEM-CHAPTER EXERCISE
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