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study the following information carefully and answer the questions given below it. An exhibition is open for pubic since 9 am till 3 pm and again since 4 pm till 10 pm in a day. There are 12 batches of 1 hour each. The entry ticket bears a pass code made up of seven words, which changes every hour following a particular rule. The pass codes for 4 pm to 10 pm are same as those for respective hours during 9 am to 3 pm i.e., the pass code for 4 pm to 5 pm is same as that of 9 am to 10 am and so on. Following is an illustration of the code and steps of rearrangement for subsequent clock hours.
First batch : 9 am to 10 am (4 pm to 5 pm)
Pass code : dig more and you will find water
Second batch : 10 am to 11 am (5 pm to 6 pm)
Pass code : and dig find you water will more
Third batch : 11 am to 12 noon (6 pm to 7 pm)
Pass code : find and will you more water dig and so on.
If the pass code for 5 pm to 6 pm is 'out in above over the field end', what will be the pass code for 1 pm to 2 pm ?

A

the field end over out in above

B

field end the over out in above

C

field the end over out above in

D

the field end over out above in

Text Solution

Verified by Experts

The correct Answer is:
A

The pattern/rule is as follows :
First step i.e., Batch I :
`underset(1)" dig "underset(2)"more"underset(3)" and "underset(4)" you "underset(5)" will "underset(6)" find "underset(7)" water "`
Second step i.e., Batch II :
3 1 6 4 7 5 2
So, in every step, the words of the previous step are arranged as follows :
3rd, 1st, 6th, 4th, 7th, 5th, 2nd
Batch I ("9 am to 10 am/4 pm to 5 pm")
1 2 3 4 5 6 7
Batch II ( " 10 am to 11 am/5 pm to 6 pm")
`underset(1st)" 3 "underset(2nd)"1"underset(3rd)" 6 "underset(4th)" 4 "underset(5th)" 7 "underset(6th)" 5 "underset(7th)" 2 "`
Batch III ("11 am to 12 noon/6 pm to 7 pm")
`underset(1st)" 6 "underset(2nd)"3"underset(3rd)" 5 "underset(4th)" 4 "underset(5th)" 2 "underset(6th)" 7 "underset(7th)" 1 "`
Batch IV ("12 noon to 1 pm/7 pm to 8 pm"):
`underset(1st)" 5 "underset(2nd)"6"underset(3rd)" 7 "underset(4th)" 4 "underset(5th)" 1 "underset(6th)" 2 "underset(7th)" 3 "`
Batch V `("1 pm to 2 pm/8 pm to 9 pm")`:
`underset(1st)" 7 "underset(2nd)"5"underset(3rd)" 2 "underset(4th)" 4 "underset(5th)" 3 "underset(6th)" 1 "underset(7th)" 6 "`
Batch VI `("2 pm to 3 pm/9 pm to 10 pm")`
2 7 1 4 6 3 5
Batch II (5 pm to 6 pm) :
`underset(3)" Out "underset(1)"in"underset(6)" above "underset(4)" over "underset(7)" the "underset(5)" field "underset(2)" end "`
So, Batch V ( 1pm to 2 pm):
`underset(7)" the "underset(5)"field"underset(2)" end "underset(4)" over "underset(3)" Out "underset(1)" in "underset(6)" above "`
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