The value of b for which the function f(...

The value of b for which the function `f(x)=x+cos x+b` is strictly decreasing over R is:
a) `b<1` b) `b<=1` c) No value of b exists d) `b>=1`

Similar Questions

Explore conceptually related problems

The function f(x) = x + cos x + b is strictly decreasing over R then:

Prove that the function f(x)=cos x is strictly decreasing in (0,pi)

Write the interval in which the function f(x)=cos x is strictly decreasing.

The function f(x)=ax+b is strictly increasing for all real x is

Show that the function f(x) = 2x+1 is strictly increasing on R.

The function f(x)=ax+b is strictly decreasing for all x epsilon R if

Find the values of b for which the function f(x)=sin x-bx+c is a decreasing function on R .

Prove that the function f(x)=[x]-x is strictly decreasing on [0,1).

Find the values of b for which the function f(x)=sin x-bx+c is a decreasing function on R.

Show that the function f(x)=a^(x),a>1 is strictly increasing on R.