If `2sin^(2)beta-cos^(2)beta` = 2 ,then `beta` is
(a ) 0°
(b) 90°
(c) 45°

If 2 sin^(2)beta -cos^(2)beta =2 , then beta is

If 2sin^(2)beta-cos^(2)beta = 2 ,then beta is (a ) 0° (b) 90° (c) 45°

If 2 sin^2 beta - cos^2 beta = 2 then beta is a. 0^o b. 90^o c. 45^o d. 30^o

If tan (alpha-beta)=(sin 2beta)/(3-cos 2beta) , then

2sin^(2)beta+4cos(alpha+beta)sin alpha sin beta+cos2(alpha+beta)=

Simplify 2sin^(2)beta+4cos(alpha+beta)sin alpha sin beta+cos2(alpha+beta)

2sin^(2)beta+4cos(alpha+beta)sinalphasinbeta+cos2(alpha+beta)=?

csc^(2)(alpha+beta)-sin^(2)(beta-alpha)+sin^(2)(2 alpha-beta)=cos^(2)(alpha-beta) where alpha,beta in(0,(pi)/(2)), then sin(alpha-beta) is equals