Home
Class 11
MATHS
The centre of circle (x+2)^2 + (y+2)^2=1...

The centre of circle `(x+2)^2 + (y+2)^2=16` is

Answer

Step by step text solution for The centre of circle (x+2)^2 + (y+2)^2=16 is by MATHS experts to help you in doubts & scoring excellent marks in Class 11 exams.

Doubtnut Promotions Banner Mobile Dark
|

Similar Questions

Explore conceptually related problems

The Center of circle (x+2)^2 + (y+4)^2 = 16 is

Find the centre of circle : (x+2)^(2)+(y+4)^(2) = 16

Knowledge Check

  • Equation of the circle with centre at (1,-2) , and passing through the centre of the circle x^(2) + y^(2) + 2y - 3 = 0 , is

    A
    `x^(2) + y^(2) - 2x + 4y + 3 = 0 `
    B
    `x^(2) + y^(2) - 2x + 4y - 3 = 0 `
    C
    `x^(2) + y^(2) + 2x - 4y - 3 = 0 `
    D
    `x^(2) + y^(2) + 2x - 4y + 3 = 0 `

  • The centre and radius of the circle (x+ 2)^(2) + (y+4)^(2) = 9 are

    A
    (2, 4) and 3
    B
    `(-2, -4) and 3`
    C
    `(-2, -4)` and 9
    D
    `(2, -4)` and 3

    • Similar Questions

    Explore conceptually related problems

    Find the centre of circle : (x+2)^(2)+(y+4)^(2) = 16

    The centre of the circle (x-a)^(2)+(y-3)^(2)=9 lies on the straight line x=y and the circle touches the circle x^(2)+y^(2)=1 externally.What are the values of alpha,beta?

    The area of the circle x ^(2) + y ^(2) = 16 "Using Integration ""___________"

    The image of the centre of the circle x^(2)+y^(2)=a^(2) with respect to the mirror x+y=1 is

    Find the equation of a circle which passes the centre of the circle x^(2)+y^(2)-6x =1 and concentric with the circle 2x^(2)+2y^(2)-8x +12y -1=0 .

    The co-ordinates of the centre of the circle 2x^(2) + 2y^(2) - 6x + 8y - 4 = 0 are ........... .

    Home
    Profile