The centre of circle `(x+2)^2 + (y+2)^2=16` is

The Center of circle (x+2)^2 + (y+4)^2 = 16 is

Find the centre of circle : (x+2)^(2)+(y+4)^(2) = 16

Find the centre of circle : (x+2)^(2)+(y+4)^(2) = 16

The centre of the circle (x-a)^(2)+(y-3)^(2)=9 lies on the straight line x=y and the circle touches the circle x^(2)+y^(2)=1 externally.What are the values of alpha,beta?

The area of the circle x ^(2) + y ^(2) = 16 "Using Integration ""___________"

The image of the centre of the circle x^(2)+y^(2)=a^(2) with respect to the mirror x+y=1 is

Equation of the circle with centre at (1,-2) , and passing through the centre of the circle x^(2) + y^(2) + 2y - 3 = 0 , is

The centre and radius of the circle (x+ 2)^(2) + (y+4)^(2) = 9 are

Find the equation of a circle which passes the centre of the circle x^(2)+y^(2)-6x =1 and concentric with the circle 2x^(2)+2y^(2)-8x +12y -1=0 .

The co-ordinates of the centre of the circle 2x^(2) + 2y^(2) - 6x + 8y - 4 = 0 are ........... .