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alpha = (F V^2)/(beta^2) loge ((2pi beta...

`alpha = (F V^2)/(beta^2) log_e ((2pi beta)/(V ^ 2))`
जहाँ F = बल, V= वेग
`alpha` व `beta` की विमाऐ ज्ञात कीजिए।

A

` [beta] = M^1 L^(-1) T^(0)`
`[alpha] = L^2 T^(-2)`

B

` [alpha] = M^1 L^(-1) T^(0)`
`[beta] = L^2 T^(-2)`

C

` [alpha] = M^1 L^(0) T^(-1)`
`[beta] = L^2 T^(-2)`

D

` [alpha] = M^1 L^(-1) T^(0)`
`[beta] = L^(-2) T^(-1)`

लिखित उत्तर

Verified by Experts

The correct Answer is:
B


`implies [alpha]=([F][V^2])/([beta^2]) implies ([2pi][beta])/([V^2]) = 1`
`implies ([1][beta])/(L^2 T^(-2))=1`
`implies [beta] = L^2 T^(-2) implies [alpha] = ([M^1 L^1 T^(-2)][L^2 T^(-2)])/([L^2 T^(-2)]^2)`
`implies [alpha] = M^1 L^(-1) T^(0)`
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