`(2x)/3 + 1` = `(7x)/15 + 3`

(2x)/3 - (7x)/15 = ?

x/3 + 1 = 7/15

(x)/(3)+1=(7)/(15)

Evaluate lim (x rarr oo) (3x ^ (2) + 5x + 1) / (7x ^ (2) + 3x-1)

(12x + 17) / (3x + 1)-(2x + 15) / (x + 7) = 3 (1) / (5), x! =-(1) / (3), -7

The point (1,2) lies inside and (3,4) outside the circle x ^(2) +y ^(2) - 7x + 15 y - c =0, if

If f(1)=3,f'(1)=(1)/(3),g(1)=-4,g'(1)=(-8)/(3) then the derivative of sqrt((f(x))^(2)+(g(x))^(2)) w.r.to x at x=1 is a) (-29)/(15) b) (7)/(3) c) (31)/(15) d) (29)/(15)

lim_ (x rarr oo) (sqrt (3x ^ (2) +1) -sqrt (2x ^ (2) -3x + 5)) / (7x + 2) =

If x/3+1=7/15 , then x/3=6/15

Divide 4x^(2) + 7x - 15 " by " x +3