Find the angle between the lines `x/1=y/2=z/3` and `(x+1)/2=(y-3)/7=(z+2)/4`

Find the angle between the lines 2x=3y=-z and 6x=-y=-4z

If the angle between the lines, x/2=y/2=z/1 and (5-x)/(-2) = (7y-14)/(p ) = (z-3)/(4) is cos ^(-1) ((2)/(3)), then P is equal to

Find the angle between the two lines 2x=3y=-z and 6x=-y=-4z .

The lines x/1=y/2=z/3 and (x-1)/(-2)=(y-2)/(-4)=(z-3)/(-6) are

The angle between the lines 2x=3y=-z and 6x=-y=-4z is

Find the shortest distance between the lines (x)/2=(y-2)/3=(z-4)/3 and (x-1)/3=(y-2)/7=(z-3)/8

The Angle between lines (x)/(1)=(y)/(2)=(z)/(3) and (x+1)/(2)=(x-3)/(-7)=(z+2)/(4)

Find the angle between the line: (x-3)/1=(y-2)/2=(z-2)/(-4) and (x-0)/3=(y-5)/2=(z+2)/-6

The direction ratios of the line of shortest distance between the lines (x-2)/1=(y-3)/4=(z+1)/3 and (x-3)/2=(y-4)/3=(z-1)/2

Find the angle between the planes 3x+y+2z=1 and 2x-y+z+3 = 0 .