(sin(90-A)cos(90-A))/(tanA)...

`(sin(90-A)cos(90-A))/(tanA)`

A

`cosA`

B

`sinA`

C

`cos^(2)A`

D

`sin^(2)A`

Verified by Experts

The correct Answer is:

C

(sin(90-A)cos(90-A))/(tanA)
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