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Propanamide on reaction with bromine in ...

Propanamide on reaction with bromine in aqueous NaOH gives:

A

Propanamine

B

Ethanamine

C

N-Methyl ethanamine

D

Propanenitrile

Text Solution

Verified by Experts

The correct Answer is:
B
`underset("Propanamide")(CH_3CH_2CONH_2 +Br_2 +4NaOH) overset(Delta)to CH_3 CH_2 NH_2 +2NaBr +Na_2CO _3 +2H_2 O`
Ethanamine This is Hoffman Bromamide reaction.
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