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Methylamine reacts with HNO(2) to form…...

Methylamine reacts with `HNO_(2)` to form….

A

`CH_3-O-N=O`

B

`CH_3-O-CH_3`

C

`CH_3OH`

D

`CH_3CHO`

Text Solution

Verified by Experts

The correct Answer is:
C
Methylamine reacts with `HNO_2` to form `CH_3 OH`.
`underset("methylamine ")(CH_3 NH_2 +HNO_2 )overset(NaNO_2 +HCI) to CH_3 -N_(2)^(+) Cl^(-) overset(H_2 O)to CH_3 OH +N_2 +HCl`
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