Home
Class 10
MATHS
Evaluate : cos 38^@ cos 52^@ - sin 38^@ ...

Evaluate : `cos 38^@ cos 52^@ - sin 38^@ sin 52^@`.

Text Solution

Verified by Experts

The correct Answer is:
0
Promotional Banner

Topper's Solved these Questions

  • INTRODUCTION TO TRIGONOMETRY AND TRIGONOMETRIC IDENTITIES

    OSWAL PUBLICATION|Exercise NCERT CORNER (Textbook Questions) (Exercise - 8.4)|18 Videos

  • INTRODUCTION TO TRIGONOMETRY AND TRIGONOMETRIC IDENTITIES

    OSWAL PUBLICATION|Exercise NCERT EXEMPLAR (Exercise - 8.1) (Choose the correct answer from the given four options)|14 Videos

  • INTRODUCTION TO TRIGONOMETRY AND TRIGONOMETRIC IDENTITIES

    OSWAL PUBLICATION|Exercise NCERT CORNER (Textbook Questions) (Exercise - 8.2)|15 Videos

  • INTRODUCTION TO TRIGONOMETRY

    OSWAL PUBLICATION|Exercise Self - Assessment |15 Videos

  • LINES (IN TWO - DIMENSIONS)

    OSWAL PUBLICATION|Exercise BOARD CORNER (LONG ANSWER TYPE QUESTION)|2 Videos

Similar Questions

Explore conceptually related problems

cos38^(@)cos52^(@)-sin38^(@)sin52^(@)=0

The value of cos38^(@)cos52^(@)-sin38^(@)sin52^(@) is :

Find the value of: (i)tan90^@ (ii) cos38^@cos52^@-sin38^@sin52^@

The value of sin^2 38^@-cos^2 52^@ is : sin^2 38^@-cos^2 52^@ का मान ज्ञात करें ।

cos 38^(@) cos 8^(@) + sin 38^(@)sin 8^(@) is equal to

Evaluate: (cos 58^@)/(sin 32^@)+(sin 22^@)/(cos 68^@)-(cos 38^@cosec 52^@)/(tan 18^@tan 35 ^@ tan 60^@tan 72^@tan 55^@) .

The value of sin^2 38^@+ sin^2 52^@+ sin^2 30^@- tan^2 45^@ is equal to: sin^2 38^@+ sin^2 52^@+ sin^2 30^@- tan^2 45^@ का मान किसके बराबर है?

The value of (2 sin^2 38^@ sec^2 52^@+ cos64^@ sin26^@+ sin^2 64^@)/(tan^2 23^@+cot^2 23^@-sec^2 67^@-cosec^2 67^@) is: (2 sin^2 38^@ sec^2 52^@+ cos64^@ sin26^@+ sin^2 64^@)/(tan^2 23^@+cot^2 23^@-sec^2 67^@-cosec^2 67^@) का मान ज्ञात कीजिए?

Without using trigonometric tables, prove that : (i) sin 43^@cos47^@+cos43^@ sin 47^@=1 (ii) cos 38^@cos 52^@-sin 52^@=0 (iii) sec 50^@sin40^@+cos40^@cosec 50^@=2 (iv) sec 70 ^@sin 20^@-cos 20^@-cosec 70^@=0

If cot 52^@ = b , tan 38^@= ?