In a right circular cone, the corss - s...

In a right circular cone, the corss - section made by a plane parallel to the base is a

circle

frustum of a cone

sphere

hemisphere

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In a right circular cone, the cross - section made by a plane parallel to the base is a (A) Circle (B) Frustum of a cone (C) Sphere (D) Hemisphere

The height of a right circular cone is trisected by two planes drawn parallel to the base. Show that the volumes of the three portions starting from the top are in the ratio 1:7:19.

A right circular cone is divided into two portions by a plane parallel to the base and passing through a point which is (1)/(3)rd of the height from the top.The ratio of the volume of the smaller cone to that of the remaining frustum of the cone is (a) 1: 3(b) 1: 9 (c) 1:26 (d) 1:27

The radius of the base of a right circular cone is r.It is cut by a plane parallel to the base at aheight h from the base.The slant height of the frustum is sqrt(h^(2)+(4)/(9)r^(2)) .Show that the volume of 13 the frustum is (13)/(27)pi r^(2)h

The height and the radius of the base of a right circular cone are 12 cm and 6 cm respectively. The radius of the circular cross-section of the cone cut by a plane parallel to its base at a distance of 3 cm from the base is

What is Right Circular cone?

The height of a right circular cone is 20 cm. A small cone is cut off at the top by a plane parallel to the base. If its volume be 1/8 of the volume of the given cone, at what height above the base is the section made?

What cross-section is made by a cone when it is cut parallel to its base?

OSWAL PUBLICATION-SURFACE AREAS AND VOLUMES -NCERT EXEMPLAR (EXERCISE-13.1)

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