A bulinding is in the form of a cylinder surmounted by a hemispherical valuted dome and surroumted by a hemispherical valulated dome and contains `41(19)/(21)m^(3)` of air. If the internal diameter of dome is equal to its total height above the floor, find the height of the bulinding ?

A bulinding is in the form of a cylinder surmounted by a hemispherical valuted dome and contains 41(19)/(21)m^(3) of air. If the internal diameter of dome is equal to its total height above the floor, find the height of the bulinding ?

A building is in the form of a cylinder surmounted by a hemispherical dome on the diameter of the cylinder. The height of the building is three times the radius of the base of the cylinder. The building contains 67 (1/21) m^(3) of air. What is the height of the building ?

There is a hemispherical roof on the cylindrical room .There is 5236 m^(3) air in this room .The inner diameter of the floor is equal to the maximum height of the room. Find the height of room . (Given that pi =3.1416)

A hemispherical roof is on a circular room. Inner diameter of the roof is equal to the greatest height of the roof. If 48510m^(3) air is inside the room, find the height of the roof.

A hemispherical roof is on a circular room. Inner diameter of the roof is equal to the greatest height of the roof. If 48510 m^(3) air is inside the room, find the height of the roof

A solid is in the form of a cylinder with hemispherical ends. Total height of the solid is 19 cm and the diameter of the cylinder is 7 cm. Find the volume and total surface area of the solid.

A room in the form of a cylinder surmounted by a hemisphere valuted dome contains 17.7 m^(3) .After recycling, this water is used to irriegate a park of hospital whose length is 25 m and breadth is 20 m. If tank is filled completely then what will be the height of standing water used for irrigting the park write you views on recycling of water.

A toy is in the form of a cone surmounted by a hemisphere whose radius is 3.5 cm . If the total height of the toy is 15.5 cm then find its total surface area and the Volume