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The polynomial y = p(x) intersects the ...

The polynomial `y = p(x)` intersects the axes at `(-3,0),(0,1),(1,0)and (3,0)`
Find the zeroes of the polynomial are :

A

`-3,0,3`

B

`-3,-1,0`

C

`-3,1,3`

D

`-1,0,1`

Text Solution

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The correct Answer is:
To find the zeroes of the polynomial \( y = p(x) \) that intersects the axes at the points \((-3,0)\), \((0,1)\), \((1,0)\), and \((3,0)\), we can follow these steps: ### Step-by-Step Solution 1. **Identify the Zeroes from the Given Points**: The zeroes of a polynomial are the x-values where the polynomial intersects the x-axis. From the given points: - The points where \( y = 0 \) are \((-3,0)\), \((1,0)\), and \((3,0)\). - Therefore, the zeroes of the polynomial are \( x = -3 \), \( x = 1 \), and \( x = 3 \). 2. **List the Zeroes**: We can now list the zeroes we found: - The zeroes are \( -3, 1, 3 \). ### Final Answer The zeroes of the polynomial \( y = p(x) \) are: \[ -3, 1, 3 \]
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