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The lines 3x-4y=9 and y=0 meet at :...

The lines `3x-4y=9 and y=0` meet at :

A

`(-3,0)`

B

`(3,0)`

C

`9/4,0`

D

`(3/2,0)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the point where the lines \(3x - 4y = 9\) and \(y = 0\) meet, we can follow these steps: ### Step 1: Substitute \(y = 0\) into the first equation We start with the equation of the first line: \[ 3x - 4y = 9 \] Since we know that \(y = 0\), we substitute \(0\) for \(y\): \[ 3x - 4(0) = 9 \] ### Step 2: Simplify the equation This simplifies to: \[ 3x = 9 \] ### Step 3: Solve for \(x\) Now, we can solve for \(x\) by dividing both sides by \(3\): \[ x = \frac{9}{3} = 3 \] ### Step 4: Write the coordinates of the intersection point Now that we have both \(x\) and \(y\), we can write the coordinates of the point where the two lines meet: \[ (x, y) = (3, 0) \] ### Final Answer The lines \(3x - 4y = 9\) and \(y = 0\) meet at the point \((3, 0)\). ---
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