The centroid of a triangle formed by `(2,p),(q,7),(3,1) is (6,3)` .then `p+q` is

If the centroid of the triangle formed by (p,q),(q,r),(r,s) is (0,0) then p^(3)+q^(3)+r^(3)=

If the centroid of the triangle formed by points P(a,b),Q(b,c) and R(c,a) is at the origin, what is the value of a+b+c?

The vertices of a triangle are (p q ,1/(p q)),(p q)),(q r ,1/(q r)), and (r q ,1/(r p)), where p ,q and r are the roots of the equation y^3-3y^2+6y+1=0 . The coordinates of its centroid are (1,2) (b) 2,-1) (1,-1) (d) 2,3)

If the origin is the centroid of the triangle whose vertices are A (2,p,-3), B(q,-2,5) and C(-5,1,r), then find the values of p,q and r.

The area of the triangle formed by the points (p,(1)/(p)); (q,(1)/(q)) and (r,(1)/(r))

If alpha,beta,gamma are the real roots of the equation,x^(3)-3px^(2)+3qx-1=0, the centroid of the triangle whose vertices are (alpha,(1)/(alpha)),(beta,(1)/(beta)),(gamma,(1)/(gamma))quad is(p,p)(b)(p,0)(p,q)(d)(q,0)

If G(3, -5, r) is centroid of triangle ABC where A(7, - 8, 1), B(p, q, 5) and C(q + 1, 5p, 0) are vertices of a triangle then values of p, q, r are respectively ...