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An observer , 1.7 m tall , is 20sqrt(3) ...

An observer , `1.7` m tall , is `20sqrt(3)` m away from a tower . The angle of elevation from the eye of observer to the top of tower is `30^(@)` . Find the height of tower .

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An observer,1.6m tall,is 45 metres away from a tower.The angle of elevation from his eye to the top of the tower is 30^(@). Determine the height of the tower.[Take sqrt(3)=1.732]

An observer 1.6m tall is 20sqrt(3)m away from a tower.The angle of elevation from his eye to the top of the tower is 30o .The height of the tower is: (a) 21.6m (b) 23.2m(c)24.72m (d) None of these

Knowledge Check

  • An observer 1.5 m tall is 28.5 m away from a tower and the angle of elevation of the top of the tower from the eye of the observer is 45^(@) . The height of the tower is

    A
    `27 m`
    B
    `30 m`
    C
    `28.5 m`
    D
    none of these

  • From 40 m away from the foot of a tower , the angle of elevation of the top of the tower is 60^(@) .What is the height of the tower ?

    A
    `(120)/(sqrt(3))` m .
    B
    `(60)/(sqrt(3))` m .
    C
    `(50)/(sqrt(3))` m .
    D
    `(130)/(sqrt(7))`m .

  • A 1.6 m tall observer is 45 metres away from a tower .The angle of elevation from his eye to the top of the tower is 30^(@) , then the height of the tower in metres is (Take sqrt(3)=1.732)

    A
    `25 . 98`
    B
    `26 . 58`
    C
    `27 . 58`
    D
    `27 . 98`

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    At a point 20 m away from the foot of a tower the angle of elevation of the top of the tower is 30^(@) The height of the tower is

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