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The mid-point of the line-segment AB is ...

The mid-point of the line-segment AB is P(0,4). If the coordinates of B are (-2, 3) then the co-ordinates of A are

A

(2,5)

B

3

C

`(13)/(2)`

D

`-(13)/(2)`

Text Solution

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The correct Answer is:
To find the coordinates of point A given that the midpoint P(0, 4) of line segment AB and the coordinates of point B are (-2, 3), we can use the midpoint formula. ### Step-by-Step Solution: 1. **Understanding the Midpoint Formula:** The midpoint P of a line segment AB with endpoints A(x1, y1) and B(x2, y2) is given by: \[ P\left(\frac{x1 + x2}{2}, \frac{y1 + y2}{2}\right) \] Here, we know: - Midpoint P = (0, 4) - Coordinates of B = (-2, 3) 2. **Setting Up the Equations:** From the midpoint formula, we can set up the following equations: \[ \frac{x1 + (-2)}{2} = 0 \quad \text{(1)} \] \[ \frac{y1 + 3}{2} = 4 \quad \text{(2)} \] 3. **Solving for x1:** From equation (1): \[ \frac{x1 - 2}{2} = 0 \] Multiply both sides by 2: \[ x1 - 2 = 0 \] Adding 2 to both sides gives: \[ x1 = 2 \] 4. **Solving for y1:** From equation (2): \[ \frac{y1 + 3}{2} = 4 \] Multiply both sides by 2: \[ y1 + 3 = 8 \] Subtracting 3 from both sides gives: \[ y1 = 5 \] 5. **Final Coordinates of A:** Therefore, the coordinates of point A are: \[ A(2, 5) \] ### Final Answer: The coordinates of A are (2, 5).
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