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A current of 1 A is drawn by a filament ...

A current of `1 A` is drawn by a filament of an electric bulb. Number of electrons passing through a cross-section of the filament in `16` seconds would be roughly :

A

`10^20`

B

`10^16`

C

`10^18`

D

`10^23`

Text Solution

Verified by Experts

The correct Answer is:
A
Given, I=1 Amp.
`t=16 s`
As `I=Q/t=(ne)/t`
`n=((1 xx T)^t)/theta=(1 xx 16)/(1.6 xx 10^-19)`
`n=10`
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