An electric bulb is rated at 200 V, 100 ...

An electric bulb is rated at 200 V, 100 W . What is its resistance ?

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Given, V = 200 volts and P =100 watt
As `P = (V^(2))/(R ) ` Or R ` = (V^(2))/(P) = ((200)^(2))/(100W) = (40000)/(100 Omega) = 400 Omega `

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