`2sqrt3+sqrt2+1/sqrt3+....`

The value of (1-sqrt2) + (sqrt2-sqrt3)+(sqrt3-sqrt4)+ ............ + (sqrt15-sqrt16) is

[(sqrt3 + sqrt2 )/(sqrt3 - sqrt2) - (sqrt3 - sqrt2)/(sqrt3 + sqrt2)] simplifies to

Simplify (1/2+1/sqrt2-sqrt3)/(sqrt3-1/sqrt2-1/sqrt3)

The value of 6+ log_(3//2) (1/(3sqrt2)sqrt(4-1/(3sqrt2)sqrt(4-1/(3sqrt2)sqrt(4-1/(3sqrt2)...)))) is ________.

The value of 6+log_(3//2)(1/(3sqrt2)sqrt(4-1/(3sqrt2)sqrt(4-1/(3sqrt2)sqrt(4-1/(3sqrt2)...)))) is

Value of 1/(sqrt2+1)+1/(sqrt3+sqrt2)+1/(sqrt4+sqrt3)+....+1/(sqrt100+sqrt99) is

Solve (1/(sqrt3+sqrt2))+(1/(sqrt3-sqrt2))

The value of the expression sqrt ((1/(sqrt2+1)+1/(sqrt3+sqrt2)+1/(sqrt4+sqrt3)+.........99 terms is equal to