The perpendicular from A on side BC of a...

The perpendicular from A on side BC of a ABC intersects BC at D such that DB = 3 CD. Prove that `2AB^2 = 2AC^2 + BC^2`.

SAMPLE PAPER - 6
EDUCART PUBLICATION|Exercise PART - B (SECTION - III)|10 Videos
REAL NUMBERS
EDUCART PUBLICATION|Exercise LONG QUESTION TYPE QUESTIONS|5 Videos
SAMPLE PAPER 12
EDUCART PUBLICATION|Exercise PART - B (SECTION -V) |4 Videos

Similar Questions

Explore conceptually related problems

The perpendicular from A on side BC of a Delta ABC meets BC at D such that DB = 3CD. Prove that 2AB^2 = 2AC^2 + BC^2

The perpendicular drawn from A on sides BC of a Delta ABC intersects BC at D such that DB = 3CD .Prove that 2AB^(2)=2AC^(2)+BC^(2) .

The perpendicular from A on side BC of a DeltaABC meets BC at D such that DB = 3CD .Prove that 2AB^(2)=2AC^(2)+BC^(2) .

The perpendicular AD on the base BC of a ABC intersects BC at D so that DB=3CD. Prove that 2AB^(2)=2AC^(2)+BC^(2)

The perpendicular AD on the base BC of a triangleABC intersects BC at D, so that DB=3CD. Prove that 2AB^(2)= 2AC^(2)+BC^(2)

In the given figure, the of a Delta ABC , interesects BC at D such DB=3CD . Prove that 2AB^(2)=2AC^(2)+BC^(2)

In a DeltaABC , altitude drawn from vertex A to side BC meets BC at D such that DB=3CD . Prove that 2AB^(2)=2AC^(2)+BC^(2)

In Delta ABC seg AD perp seg BC,DB=3CD Prove that 2AB^(2)=2AC^(2)+BC^(2)

In DeltaABC , seg AD bot seg BC , DB=3CD . Prove that 2AB^(2)=2AC^(2)+BC^(2) .